Not sure which Canon body to get

jdramirez said:
traingineer said:
jdramirez said:
traingineer said:
It seems that the 7D is getting no love... ;~;

Image quality won't be improved because they share the same sensor. Most of the things he shoots are stationary and don't require an advanced auto focus system or a higher frames per second rate.. so that's why.

I'm a fan of the 7d and getting it used for $700 is a steal, but it is all about the body that is right for the shooter.

700$, That is pretty cheap.

About 2 or three months ago, I bought a used 7D with less than 2500 actuations and a 28-135 for the bargain basement price of $650. I then turned around and sold the 7D for 700ish and the lens for 200ish... so I made an easy $250ish.

So... yeah... cheap.

Cool. (ツ)
 
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CarlTN said:
jdramirez said:
traingineer said:
jdramirez said:
traingineer said:
It seems that the 7D is getting no love... ;~;

Image quality won't be improved because they share the same sensor. Most of the things he shoots are stationary and don't require an advanced auto focus system or a higher frames per second rate.. so that's why.

I'm a fan of the 7d and getting it used for $700 is a steal, but it is all about the body that is right for the shooter.

700$, That is pretty cheap.

About 2 or three months ago, I bought a used 7D with less than 2500 actuations and a 28-135 for the bargain basement price of $650. I then turned around and sold the 7D for 700ish and the lens for 200ish... so I made an easy $250ish.

So... yeah... cheap.

Did you report this as capital gains? :P...

All my money is in the cook islands... sons a bitches won't give it back though. :/
 
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Hi, could you please show how you arrived at this formula! :o
BODMAS being the first principle, (0x)10 I still recon this equals zero even if x is an unknown, anything (x) times 0=0, 0x10 =0 so are you saying 6D +0 = 7D? Or is my calculus (basically unused for 20 yrs) really that rusty? :'(
I stand to be corrected, perhaps we are using cypher principles rather than mathematical principles? ::) ;D ;D

Cheers Graham.


dgatwood said:
neuroanatomist said:
For the uses listed, the 6D is the better choice, budget permitting.

tolusina said:

I was going to say +1, but 6D + 1 = 7D, and that's not what I mean. ;)

No, 6D + 1 = 6E. 6D + (0x)10 = 7D. :D
 
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Valvebounce said:
Hi, could you please show how you arrived at this formula! :o
BODMAS being the first principle, (0x)10 I still recon this equals zero even if x is an unknown, anything (x) times 0=0, 0x10 =0 so are you saying 6D +0 = 7D? Or is my calculus (basically unused for 20 yrs) really that rusty? :'(
I stand to be corrected, perhaps we are using cypher principles rather than mathematical principles? ::) ;D ;D

Cheers Graham.


dgatwood said:
neuroanatomist said:
For the uses listed, the 6D is the better choice, budget permitting.

tolusina said:

I was going to say +1, but 6D + 1 = 7D, and that's not what I mean. ;)

No, 6D + 1 = 6E. 6D + (0x)10 = 7D. :D

I saw it... and I thought there would be a joke somewhere than I'm not getting.

6D9 + 1= 6E Ok... Then we need to solve for D since that is use in the next equation.

D=(6e-10)/6

ok

So plug that into the next equation which gives us...


6*(6e-10)/6+(0x)10=7*(6e-10)/6

So... reduce... and we get to

6e-10+0=(42e-70)/6

6e-10=7e-11.66
6e=7e-1.66
1.66=1e
ergo e=1.66

plug that into the equation above...

D=(6*1.66-10)/6
d=(10-10)/6
d=0/6
d=0


So yeah...

I loved calculus 1 and 2 and got my ass kicked in calc three... so one day when I'm retired... I'll happily go back and audit some calc classes... for shitz and giggz.
 
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jdramirez said:
Valvebounce said:
Hi, could you please show how you arrived at this formula! :o
BODMAS being the first principle, (0x)10 I still recon this equals zero even if x is an unknown, anything (x) times 0=0, 0x10 =0 so are you saying 6D +0 = 7D? Or is my calculus (basically unused for 20 yrs) really that rusty? :'(
I stand to be corrected, perhaps we are using cypher principles rather than mathematical principles? ::) ;D ;D

Cheers Graham.


dgatwood said:
neuroanatomist said:
For the uses listed, the 6D is the better choice, budget permitting.

tolusina said:

I was going to say +1, but 6D + 1 = 7D, and that's not what I mean. ;)

No, 6D + 1 = 6E. 6D + (0x)10 = 7D. :D

I saw it... and I thought there would be a joke somewhere than I'm not getting.

6D9 + 1= 6E Ok... Then we need to solve for D since that is use in the next equation.

D=(6e-10)/6

ok

So plug that into the next equation which gives us...


6*(6e-10)/6+(0x)10=7*(6e-10)/6

So... reduce... and we get to

6e-10+0=(42e-70)/6

6e-10=7e-11.66
6e=7e-1.66
1.66=1e
ergo e=1.66

plug that into the equation above...

D=(6*1.66-10)/6
d=(10-10)/6
d=0/6
d=0


So yeah...

I loved calculus 1 and 2 and got my ass kicked in calc three... so one day when I'm retired... I'll happily go back and audit some calc classes... for shitz and giggz.

It's counting in Hexadecimal...

0 1 2 3 4 5 6 7 8 9 A B C D E F 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F 20 21.....

67 68 69 6A 6B 6C 6D 6E 6F....

and 6D(hex) + 10(hex) = 7D(hex)

Sad thing is, I'm old enough to have programmed bootstrap loaders in Octal and binary.... loading it in with toggle switches...
 
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Hi Don.
Damn it is so sad when a clever joke has to be explained to the recipients! It would have been so much funnier if I got it whilst it was fresh!
Thanks for explaining it Don, sorry for not getting it dgatwood, it was clever! :-[

Cheers Graham.
 
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Don Haines said:
jdramirez said:
Valvebounce said:
Hi, could you please show how you arrived at this formula! :o
BODMAS being the first principle, (0x)10 I still recon this equals zero even if x is an unknown, anything (x) times 0=0, 0x10 =0 so are you saying 6D +0 = 7D? Or is my calculus (basically unused for 20 yrs) really that rusty? :'(
I stand to be corrected, perhaps we are using cypher principles rather than mathematical principles? ::) ;D ;D

Cheers Graham.


dgatwood said:
neuroanatomist said:
For the uses listed, the 6D is the better choice, budget permitting.

tolusina said:

I was going to say +1, but 6D + 1 = 7D, and that's not what I mean. ;)

No, 6D + 1 = 6E. 6D + (0x)10 = 7D. :D

I saw it... and I thought there would be a joke somewhere than I'm not getting.

6D9 + 1= 6E Ok... Then we need to solve for D since that is use in the next equation.

D=(6e-10)/6

ok

So plug that into the next equation which gives us...


6*(6e-10)/6+(0x)10=7*(6e-10)/6

So... reduce... and we get to

6e-10+0=(42e-70)/6

6e-10=7e-11.66
6e=7e-1.66
1.66=1e
ergo e=1.66

plug that into the equation above...

D=(6*1.66-10)/6
d=(10-10)/6
d=0/6
d=0


So yeah...

I loved calculus 1 and 2 and got my ass kicked in calc three... so one day when I'm retired... I'll happily go back and audit some calc classes... for shitz and giggz.

It's counting in Hexadecimal...

0 1 2 3 4 5 6 7 8 9 A B C D E F 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F 20 21.....

67 68 69 6A 6B 6C 6D 6E 6F....

and 6D(hex) + 10(hex) = 7D(hex)

Sad thing is, I'm old enough to have programmed bootstrap loaders in Octal and binary.... loading it in with toggle switches...

Reminds me of the old programmers joke:
There are only 10 types of people in the world, those who understand binary and those who don't.:)

Phil.
 
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Don Haines said:
...

It's counting in Hexadecimal...

0 1 2 3 4 5 6 7 8 9 A B C D E F 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F 20 21.....

67 68 69 6A 6B 6C 6D 6E 6F....

and 6D(hex) + 10(hex) = 7D(hex)

Sad thing is, I'm old enough to have programmed bootstrap loaders in Octal and binary.... loading it in with toggle switches...

Remember the IMSAI 8080 fondly myself - 2Mhz clock cycle and 64K bytes RAM max ::) Fortunately that phase passed fairly quickly. :)
 
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philmoz said:
Reminds me of the old programmers joke:
There are only 10 types of people in the world, those who understand binary and those who don't.:)

Phil.

That and... There are two hard problems in computer science: cache invalidation, naming things, and off-by-one errors.
 
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shamlyn said:
Here is what I shoot: Landscape, wildlife, light trails, sunrises and sunsets

If you think of wildlife as "tracking moving animals" then forget the 6d, the servo capability is abysmal (basically center point only, outer points are useless as is multi-point af mode). For everything else it depends on what image quality you want to get, it doesn't sound like you need the thin depth of field of full frame and 70d is certainly "good enough" for everything you at an ok price... though it doesn't run Magic Lantern.
 
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alexturton said:
tolusina said:

+1

7d and 5dii are dated.

70d ok but ff > crop

Crap... I confused my threads... so disregard the parts where I mention real estate photography.

I think dated might be overstating it... I've either owned or played with an XS, XTi, 50D, 60d, and 5D mkiii.

So the 10.1, 15.1, 18, and 22.3 full frame.

In good light and @ iso 100/160, I'd trust any of those bodies... which means using a tripod, using off camera lighting, etc.

When I wouldn't trust the 18 on down, is in questionable light, with moving targets, and high isos...

I was editing some photos taken by my daughter with an SL1 in pretty bad light in a church... and it REALLY made me appreciate the mkiii.

But for real estate... generally the walls and the furniture don't move. And with all of them you can and probably will do high dynamic range images, so the dynamic range of the lessor sensors is negated.

The fact of the matter is that a good photographer can get more then adequate results using lessor gear... and while the 6D is probably the best option, money wasn't described as a constraint.
 
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Hi JD.
I think there is at least one person on here that can prove the reverse of that statement, a poor photographer can get lesser results using adequate gear! I am of course talking about myself! ::)
Struggling to become a better photographer.

Cheers Graham.

jdramirez said:
The fact of the matter is that a good photographer can get more then adequate results using lessor gear... and while the 6D is probably the best option, money wasn't described as a constraint.
 
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Valvebounce said:
Hi JD.
I think there is at least one person on here that can prove the reverse of that statement, a poor photographer can get lesser results using adequate gear! I am of course talking about myself! ::)
Struggling to become a better photographer.

Cheers Graham.

jdramirez said:
The fact of the matter is that a good photographer can get more then adequate results using lessor gear... and while the 6D is probably the best option, money wasn't described as a constraint.

When I first took up golf... I had a crap set I bought for $100... I played the crap out of the clubs and I did pretty well with a patchwork set. I'd compare that with my XS and 50mm f/1.8.

After a few years... I upgraded my clubs to a $300 driver (which was 15 years ago... so after inflation... $500ish) and a set of irons from Taylormade and a putter and wedges...

I wanted the gear not to be the reason I had a crappy shot... So... my 5D mkiii and lenses are comparable to that. When I screw up a shot... I KNOW I'M TO BLAME. It sucks... I liked when it was my XS or 60D that were the problem.
 
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