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Solution :

To prove- `/_E=1/2/_A`<br>
By exterior angle theorem<br>
`/_A+/_B=/_ACD`<br>
`1/2/_A+1/2/_B=1/2/_ACD`<br>
`1/2/_A+/_1=/_2`<br>
`/_2=/_1+1/2/_A-(1)`<br>
`In /_\BCE`<br>
`/_ECD=/_1+/_E`<br>
`/_2=/_1+/_E-(2)`<br>
From equation 1 and 2<br>
`/_1+/_E=/_1+1/2/_A`<br>
`/_E=1/2/_A`.