neuroanatomist said:
I'm not sure about 'the DR of a sensor scales with area'. Looking at the DxOMark scores, both the 7D and the 5DII have a higher DR than the original 5D. Larger pixels have a higher full well capacity, but DR is not determined solely by full well capacity (dark noise and in-sensor processing also play major roles).
Dark noise is important for long exposures (second or longer), for shorter exposures read-out noise is more important. Read-out noise depends on the electronics, but usually scales with the number of pixels - the read-out noise per pixel is usually similar for similar-generation cameras. E.g., 7D has 2.7 electrons/pix and 5D2 2.5 electrons/pix in read-out noise.
For well-exposed images the full-well capacity is far more important, however, since the Poisson noise will far out-weight the read-out noise. The full-well for a 7D pixel is 24800 electrons, while the 5D2 can accommodate 65700 electrons/pixel (i.e. close to the ratio of their pixel areas: (6.4/4.3)^2 = 2.22 while 65700/24800 = 2.65, so the 5D2 is actually doing a little bit better per area). For a full well, the Poisson noise contribution is thus sqrt(24800) = 157 photo-electrons for the 7D and 256 photo-electrons for the 5D2 (much higher than their read-out noise).
In general, the signal-to-noise (S/N) per pixel is S/N =
P / sqrt(
P+R^2), where
P is the number of photo-electrons and
R is the readout noise. So the 5D2 gives higher S/N per pixel than 7D. That's why the 5D2's pixels are thought to be "cleaner" or "higher quality" than the 7D pixels.
neuroanatomist said:
I don't know of any test like this (TDP has sharpness and some distortion tests with/without extenders). But, when I did
this test, I looked at DR (a backlit Stouffer step wedge with exposure adjusted so the lightest step was just below clipping).
It's a great service to the community you do by making those tests, I thank you for it. I don't think it is directly related to what I'm aiming at here. The test where you compared 5D2+135/2.0 to 7D+85/1.2 comes closer, since the 135/2.0 is almost like using a 85/1.2+TC1.4x (but not quite of course - there's a ~14% difference). What matters is the S/N per solid angle, and if the 5D2 provides a larger well for a solid angle, then it should provide higher DR. It should of course also take a longer exposure to fill that well, so exposure times would
not be equal.
Just to be clear, my question is:
for a given lens (say 400/2.8 )
and otherwise perfect conditions (no motion blur, good manual focus, well-lit scene etc)
what combination would give the best S/N per solid angle for an optimally exposed image (no high-light clipping):
a 7D, or a 5D2+TC1.4x?
It sounds like this test should be easy to make, I'd be tempted to try it myself if you don't beat me to it.
(I pulled read-out noise and full well data from
Clarkvision)
scalesusa said:
A TC will not improve DR, it just increases the apparent focal length of a lens. If that were true, the DR of a 10mm lens would be horrible, and for a 600mm lens, it would be extremely high.
Funny that you give this example, because I believe it to be exactly true. The DR of a 10mm is horrible compared to a 600mm
if you look at the DR per solid angle. Just think of it this way: The total number of photo-electrons of a scene in a well-exposed 10mm lens image should equal the total number of photo-electrons of a 600mm lens image. But the solid angle ("field of view") of the 600 mm lens image is much smaller than the 10 mm image - thus the number of photo-electrons per solid angle is much higher in the former case. Since DR in the high-photo-electrons limit is determined by the number of photo-electrons recorded, the DR is also higher.
Or, think of producing the 10mm image by making a huge mosaic of 600mm images. Then it becomes obvious that the latter should provide a higher DR.