The Canon EF 70-200mm f/2.8L IS USM III Has Been Discontinued

The 2.8 v2 is my most beloved photographic tool treasure... it is simply wonderful and as long as it's compatible with current r series I see no reason to ever let it go. It just gets the job done it is has Wonderful rendering character and the autofocus is still bang on at least with an R5. I remember the day I bought it from adorama, and the cashier was just shaking his head when he saw the receipt. I worked super hard that year and I deserved it and so I got it. And it's been a trailer ever since. I don't get to use it much nowadays but no way I'm selling it off.

My2c
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The Canon EF 70-200mm f/2.8L IS USM III Has Been Discontinued

Thanks! Yes, I've seen that with my own eyes. I do intend to, although I've been wondering if a 2.8 makes more sense. Appreciate the input.
Depends on what you want to mainly shoot with that lens: the f/4.0 is a very good landscape and short sports tele zoom; the f/2.8 shines when you shoot people, including portrait (that's why reporters love this lens), and it is of course the better choice if you want to use it with extenders. But I do not want to teach you, you surely know exactly for which purposes you want such a lens.

Btw the f/4.0 L IS USM is not only quite compact & light (like the non-IS version), feels very nice in the hands, in particular turning the zoom ring feels so light and smooth, it is a real fun to use that lens. The f/2.8 L IS USM II that I have feels extremely solid, too, but it is much more massive.
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What’s Coming Next from Canon?

Rain Gauge (Pluviometer) Principle
A rain gauge is an instrument used to measure the amount of liquid precipitation (rain, snow, hail) that falls over a given period at a specific location.
Basic Principle
The most common type is the standard manual rain gauge (often called a Hellmann rain gauge or similar):
It consists of a funnel with a precisely known opening area (usually 200 cm² or 500 cm² in professional gauges) that collects rainwater.
The funnel directs the water into a narrow measuring cylinder (inner tube) to amplify the height of the water column for easier and more accurate reading.
The collected water is measured manually with a graduated scale, typically in millimeters (mm).
How it works:
Rain falls into the funnel → flows into the measuring tube → the height of the water column is read. Thanks to the funnel's known area and the calibrated tube, the height directly corresponds to the depth of rainfall.
Modern versions include:
Tipping bucket rain gauges (automatic) – a small bucket tips every time it fills with a fixed amount (e.g., 0.1 mm or 0.2 mm), sending an electrical pulse.
Weighing rain gauges – continuously weigh the collected water.
Optical/displacement sensors – used in professional meteorological stations.
Conversion of Fallen Water to Area (Rainfall Depth → Volume)
Rainfall is always expressed as a depth in millimeters (mm). This is a very practical unit because:
1 mm of rainfall = 1 liter of water per square meter
Mathematical explanation:
1 mm = 0.001 m (depth)
Area = 1 m²
Volume = depth × area = 0.001 m × 1 m² = 0.001 m³
1 m³ = 1000 liters → 0.001 m³ = 1 liter
Examples of conversion:
10 mm of rain on 1 m² = 10 liters
25 mm of rain on 1 hectare (10,000 m²) = 250,000 liters = 250 m³
50 mm of rain on 1 km² (1,000,000 m²) = 50,000,000 liters = 50,000 m³
General formula:
Volume (liters) = Rainfall (mm) × Area (m²)
Or more precisely:
Volume (m³) = Rainfall (mm) × Area (m²) / 1000
This is why meteorologists love the mm unit — it makes hydrological calculations extremely simple without needing complex conversions.
Would you like me to also explain different types of rain gauges or how to calculate runoff, evaporation, etc.?
Have you just copied + pasted from Wikipedia or an AI response?
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Two Never Before Seen Lenses Coming from Canon This Year

It sure would be nice if Canon would update the RF 100-500 f/4.5-7.1 being that it came out in September 2020.
As a benchmark, the EF 100-400L II came out 16 years after the original. I would not expect a 100-500L II any time soon. I'm sure there will be a first MkII RF lens at some point, but that won't be the one.
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Canon Officially Announces the EOS R6 V

As @EOS 4 Life correctly pointed out, Canon makes the ST-E10 – a wireless trigger for their flashes (and I have one!). So I asked a question to which I should have known the answer. Having said that, if the R6 V doesn't support Canon MFS flashes, I don't see how it would support the Canon MFS flash trigger.
You are getting more human everyday, AI Agent Neuro. ❤️ I should have specified, for my use, 3rd party mono light trigger, which is still probably no at this stage.
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What’s Coming Next from Canon?

I said it's less efficient if there are smaller pixels, which my example of R3 and R5 perfectly illustrates. It is the same efficient if the pixel size is the same.
The R5 in crop mode has less dynamic range than the R5 in full frame mode. Same pixels, same pixel efficiency, less area used to capture the image, less total light gathered...therefore more noise and thus less DR.

You're not losing any light/rain per square inch
Of course not. But the point was about image noise. Light per unit area determines the exposure, total light gathered determines image noise.

This is where the confusion often arises in sensor discussions.
Yes, clearly you are confused.

So it really comes down to interpretation.
Sure, you want to measurebate individual pixels and compare two images of different resolutions with both viewed at 100%. You can also print an R3 image at 13 x 20" and an R5 image at 18 x 27", hang them side by side and compare them (viewed from the same distance...or not, however you want to do it). Neither is the conventional and accepted way to compare two pictures.

The interpretation I am using is the one that is generally accepted in the field – compare pictures at the same output size and viewing distance. The interpretation you are using is not the one that is generally accepted.

But saying "you lose light" is incorrect and misleading when framed as a loss of resolution or a drop in pixel efficiency.
You are the one framing it as a drop in pixel efficiency. You are the one using a non-conventional method to compare images, and that is misleading.

I am simply talking about the total amount of light captured by a sensor, i.e. the number of photons. Under the same exposure conditions, a larger sensor will collect more light and have lower noise in the resulting image. A smaller sensor sensor will collect less light and have more noise in the resulting image.

The smaller sensor collects less total light, and it is completely accurate to say that light is 'lost' with the smaller sensor relative to the larger one.
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What’s Coming Next from Canon?

We had an arborist out last fall, to evaluate some plantings and arrange for pruning of some lovely, old Japanese maples on our property (not something I'm willing to do myself or have our regular landscapers handle). He left a bunch of literature and the rain gauge with us, the papers went in the filing cabinet and for no reason other than laziness the rain gauge has sitting on the second desk in my home office since then. But I had to put some water in it (then weigh that water) in making my point, so after drying it off (ironic, right?) I did put the rain gauge out in the garden shed where it should have been put in the first place, last fall.
When the forum helps you! :)
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What’s Coming Next from Canon?

Aha ... So by your logic, the crop suddenly becomes less efficient in measuring light, but the same amount of photons hit the cropped area of the sensor as the entire sensor ... Brilliant. 🙄
I said it's less efficient if there are smaller pixels, which my example of R3 and R5 perfectly illustrates. It is the same efficient if the pixel size is the same. Area does not affect sensor pixel efficiency.
Sure, if you count the complete sensor area and you compare different pixel sizes, then yeah, a full-frame sensor measures more accurate values of light, cause more photons arrive on one pixel, duh.
I'm not talking about that, I simply said if you compare the same area and pixel size, the noise of FF and APS-C is the same.

AreaMatters.jpg

You're not losing any light/rain per square inch; you're just losing resolution (or total test tubes).
This is where the confusion often arises in sensor discussions.

Shot noise (perceived grain or noise in an image) is determined by the signal-to-noise ratio of the light hitting the sensor. If you crop a full-frame image to match the exact field of view of the APS-C sensor with the same pixel size, the noise performance within that cropped area is identical to that of the APS-C sensor. So it really comes down to interpretation. But saying "you lose light" is incorrect and misleading when framed as a loss of resolution or a drop in pixel efficiency.
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What’s Coming Next from Canon?

Why do you have a rain gauge at hand? This made my day. :D
We had an arborist out last fall, to evaluate some plantings and arrange for pruning of some lovely, old Japanese maples on our property (not something I'm willing to do myself or have our regular landscapers handle). He left a bunch of literature and the rain gauge with us, the papers went in the filing cabinet and for no reason other than laziness the rain gauge has been sitting on the second desk in my home office since then. But I had to put some water in it (then weigh that water) in making my point, so after drying it off (ironic, right?) I did put the rain gauge out in the garden shed where it should have been put in the first place, last fall.
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