So, your lack of education doesn't let you comprehend that the value you want Canon to display on LCD doesn't physically exist, but is just a "convenient" lie, like Santa Claus?fullstop said:OMFG ... "incessant semantics nitpicking". A telltale characteristic ofKit. said:Percentage of what? Do you really not know which physical property you mean by "charge" here? Looks so.Canapo... errm a few esteemed fellow forum members here.
That's electric charge, which in SI is measured in coulombs (C; 1 mAh = 3.6 C).fullstop said:100% = full charge = as printed on battery.
That's voltage - electric potential difference, measured in volts (V) - a completely different unit. All they have in common is that voltage multiplied by electric charge is energy (or work; measured in SI in joules, J).fullstop said:0% = voltage drops so low, that camera is no longer operational; not including sometimes possible stop gap measures like taking out and re-inserting for a few more shots. [whatever the specific voltage value for a specific camera model is - it is available to firmware].
And what is exactly a "midpoint" between coulombs and volts? Is it square root of joules? Or what?fullstop said:50% = midpoint between 100 and 0% as per definition above.
(how you would expect a camera + a battery to calculate this crap for you is another question)
Upvote
0